C++ program to check whether number is armstrong or not

A number in which the sum of cube of its individual digits is equal to the number itself is called Armstrong number

For Example: 1^3 + 5^3 + 3^3 = 153
4 * 4 * 4 + 0 * 0 * 0 + 7 * 7 * 7 = 407 is an Armstrong number.

C++ program which takes input a number and check whether it is Armstrong Number or not.

C++ program to check whether number is armstrong or not

 #include<iostream.h>
  using namespace std;
  int main()
  {
  int armstrong=0,num=0,result=0,check;
  cout<<"Enter Number to find it is an Armstrong number ";
       cin>>num;
       check=num;
       for(int i=1;num!=0;i++){
           armstrong=num%10;
           num=num/10;
           armstrong=armstrong*armstrong*armstrong;
           result=result+armstrong;
       }
       if(result==check){
       cout<<check<<"  is an Armstrong Number";
       }
       else{
       cout<<check<<"  is NOT an Armstrong Number";
       }
       return 0;
    }

Output

Enter Number to find it is an Armstrong number 153

153 is an Armstrong Number